Q.For a L.P.P, Minimise z = x1 + 5x2 – 3x3, Subjected to 2x1 + x2 + x3 = 5, 3x1 – x2 + 4x3 = 5, x1, x2, x3 ≥ 0, the solution (1, 2, 1) is–
Correct answer: A feasible but not basic solution
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