Q.The objective function of the dual problem of the following primal problem is – Max (z) = 3x1 – 3x2 s.t. x1≤4 x2≤6 x1+x2≤5 –x2≤–1 X1,x2≥0
Correct answer: Max (Z’) = –4w1–6w2–5w3+w4
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Math Chapter Wise question with answer
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