Math Chapter Wise Ordinary And Partial Differential Equations, Integral Equations And Calculus Of Variations English MCQ UP PCS (Pre) 1996 Q.Solution of the differential equation x 2 2 (2D 1) y 4e Ay = (c1 + c2x) e–x/2 By = 2 x / 2 1 2 1 c c x x e 2 − + + Cy = 2 x / 2 1 2 1 c c x x e 4 − + + DNone of these where c1 and c2 are arbitrary constants. Show answer Correct answer: y = 2 x / 2 1 2 1 c c x x e 2 − + +