Q.Let y = x, y = e–x be two linearly independent solution of the corresponding homogeneous equation of () 2 d y dy 1+ x + x y = (1+ x). dx dx − − If yp = u(x)x + v(x) e–x be the particular solution of the non-homogenous equation, then:
Correct answer: u(x) = x, v(x) = ex (1 – x)