Q.If I1 = () ∫ x 2 e dx, 1+x () ∫ x 2 2 2 xe I = dx, 1+ x () ∫ 2 x 3 2 2 x e I = dx, 1+ x then I1 –2I2 + I3 =
Correct answer: () x 2 e c 1 x +
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