Q181.3 5 7 9 tan tan tan tan tan 20 20 20 20 20 π is equal to:
Correct answer: 1
Q182.The general value of θ satisfying the equation 2 2sin 3sin 2 0 θ − θ − = θ − θ − = θ − θ − = θ − θ − = is:
Correct answer: (1) 7 / 6 n nπ + − π
Q183.2 2 b c cosB cosC − + ∑ ∑ is equal to:
Correct answer: 0
Q184.If a ∆ ∆ ∆ABC, b = 3 +1, c = 3 –1, ∠ ∠ ∠A = 60°, then the value of 1 tan (B C) 2 − − is:
Correct answer: 1
Q185.In a ∆ ∆ ∆ABC, 1 1 tan (A B).cot (A B) 2 2 + − + − is equal to:
Correct answer: −a b/+
Q186.If 3, 3, 3 3 are the sides of a triangle, then the angles of the triangle are:
Correct answer: 2,, 6 6 3 π
Q187.If an angle θ is divided in to two parts in such a way that the tangent of one part, is K time of the tangent of the other part and φ is equal to the difference of the two parts. then sinθ will be equal to?
Correct answer: k 1 sin k 1 + φ −
Q188.What is the time period of ((())) ((()) f x tan 3x 2 = + will be:
Correct answer: 3/π
Q189.The value of 1 1 3 4 tan sin cos 5 5 − − is equal to:
Correct answer: 24/7
Q190.If the value of θ in the second quadrant, then the value of 1 1 − + + + − sin sin sin sin θ will be:
Correct answer: 2 secθ
Q191.If m sinθ = n sin (θ+2α) then tan (θ +α) cot α is equal to:
Correct answer: −m n/+
Q192.Given 3sinθ + 5cosθ = 5, then the value of (3cosθ –5sinθ)2 is equal to
Correct answer: 9
Q193.The equation 6sin2 θ– 5sinθ +1 = 0 is satisfied by:
Correct answer: θ = 6 π
Q194.The value of tan5° ° °tan10° ° °tan15° ° °tan20° ° °....tan85° ° ° is
Correct answer: 1
Q195.The value of sin 105° ° ° is
Correct answer: 3 1 2 2 +
Q196.If α and β are angles in the first quadrant, tan α = 1 7, sinβ 1 10 = then value of (α + 2β) is
Correct answer: 45°
Q197.If b tan θ = a, then value of asin bcos asin bcos θ− θ + θ + θ + θ + θ is
Correct answer: 2 2 a b − +