Q341.x 4 cosx sinx lim x 4 π → − π − is equal to:
Limit, Continuity And Differentiability Of Function Of One Variable questions
Q342.The function f(x) defined by = + = 1/ x 1 f(x) 1 2 f(0) 1 is discontinuous at:
Q343.1 x x x x lim(3 4) is equal to –
Q344.The value of 2 cot x x 0 lim(cosx) → is–
Q346.If f (3) = 4 and f'(3) = 1, then x 3 xf(3)- 3f(x) lim x - 3 →
Q347.If ≠ 2 1 f(x) = sin x, x 0 x f(0) = 0, x =0 then at x = 0 which of the following is true?
Q348.The value of →∞ 1 n x n! lim is n
Q349.→ π x 4 2cos x -1 lim equals cotx -1
Q350.If ≤ x + 2,when x 1 f(x) = then 4x -1,when x > 1
Q351.The function e f(x) = log x is
Q352.If u = emx (y–z) y = m sin x, z = cos x then du dx is
Q353.If sin x 2 f(x) sin x cos x 2 2 π = π + then 1 2 30 f f............f 31 31 31 + + is equal to
Q354.Value of →∞ x 1 1 1 1 lim + + +....... 1+ n 2+ 2n 3+ 3n n+ nm is
Q355.The value of → tan 2x x π/4 lim (tan x) is
Q356.A function f is defined as ≠ 3 2 tan x f (x) = for x 0 and f(0) 0 x =. Then
Q357.The differential coefficient of 1 2 2x tan 1 x − with respect to 1 2 2x sin 1 x − + is equal to
Q358.n lim →∞ 2 2 2 2 1 2 3 n + + +....... 1-n 1-n 1-n 1-n is equal to
Q359.→∝ 1 n n n n lim(4 + 5) is equal to
Q360.The derivative of sin–1 x with respect to -1 2 cos 1- x is equal to
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